Kall fusion

[0038]Considering that about 106 tons nickel for year are produced through the world and since, as it will be disclosed hereinafter in Table 1, 1 g nickel would generate an energy amount equivalent to that produced by 517 tons oil, thus the yearly produced nickel amount, assuming that only 1/10,000 generates nuclear processes, will provide 1,000,000,000,000*517/10000=51,700,000,000 (oil equivalent) ton per year

Read more: http://www.faqs.org/patents/app/20110005506#ixzz1CSLgCbTI

517 ton olja / (0.83 kg/liter) * (ca 10 KWh/liter) -> 6.23 GWh = 22.4 TJ från olja

0.001 kg Ni / ( 9.6311* 10^-26 kg = Ni(58)) -> 10.38*10^21 stycken Ni(58)

22.4 TJ / (10.38*10^21 ni(58)) / (1.602*10^-19) -> 13.5 GeV energi från varje nickelkärna.

TABLE 1

[0074]Determining the energy produced by a nickel mol.

[0075]1 nickel mol=58 g

[0076]Avogadro number 6.022×1023 mol-1=number of nickel atoms in 58 g nickel.

[0077]The energy generated in each hydrogen capture process has been evaluated (for each nickel isotope) from the difference between the initial mass (nickel+hydrogen) and the reaction end product mass.

[0078]A reasonable estimate, considering the different values for the different isotopes, is 10 MeV electron (a MeV corresponds to a million electron-volts and is the energy measuring unit, as conventionally used in nuclear physics).

[0079]Since 1 Mev is equivalent to a variation of mass of 1.78×10-30 kg, the mass variation corresponding to an energy emission of 10 Mev is 1.78×10-29 kg.

[0080]The mass loss corresponding to a transformation of an entire Ni mol can be calculated by multiplying the Avogadro number (6.022×1023) time the mass variation of the single reaction.

[0081]Thus is obtained (for 58 g Ni)

[0082]M=(6.022×1023)×1.7.8×10-29 kg=1.07×10-5 kg

[0083]From the Einstein equation we have

[0084]E=mc2 where c is the light speed c=3×108 m/s.

[0085]Thus, by replacing:

[0086]J=1.07×10-5×(3×108)2=9.63×10.- sup.11 J which can be approximated to 0.3×109 kcal (which can be approximated by defect to reserve).

[0087]This is an energy equivalent to about 30,000 ton oil considering a pci of 10,000 kcal/kg for mineral oil; thus, 58 g nickel will generate the same energy as that provided by 30,000 ton oil, that is 517 tons/gram.



Read more: http://www.faqs.org/patents/app/20110005506#ixzz1CeG8nGCn

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-"När de har delat energiinnehållet i 58 gram nickel (0.3*10^9 Kcal) med energin i 1 kg olja (10000 Kcal/kg) så fick dom 30 000 ton olja, men svaret bör väl bli 30 000 kg olja, eller 30 ton olja?,"
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eller?