Citat:
Ursprungligen postat av
Moonracer
visa att ((cos^2x)/(1-cos x))-(cos x/tan^2x)=cos^2x/sin^2x
Jag kommer ända hit men sedan tar det stopp
cos^2x(1-cosx)/sin^2x=cos^2x/sin^2x
Hur får jag bort (1-cosx)
cos(x)^2/(1-cos x) - cos(x)/(tan(x)^2)
cos(x)^2/(1-cos x) - cos(x)/(sin(x)^2/cos(x)^2)
cos(x)^2/(1-cos x) - cos(x)^3/sin(x)^2
cos(x)^2/(1-cos x) - cos(X)^3/(1-cos(x)^2
Förläng cos(X)^2 med 1+cos(x) ge:
cos(x)^2*(1+cos(x))/(1-cos(x)^2) - cos(x)^3/(1-cos(x)^2)
= (cos(x)^2*(1+cos x) - cos(x)^3)/(1-cos(x)^2
= (cos(x)^2 + cos(x)^3 - cos(x)^3)/(1-cos(x)^2)
= (cos(x)^2)/(1-cos(x)^2)
Men cos(x)^2+sin(x)^2=1 ger 1-cos(x)^2=sin(x)^2
= cos(x)^2/sin(x)^2
= (cos(x)/sin(x))^2