Kod:
((3x²−29x+94)/(x−5)(x+1)(x−6)) − (3/(x+1)) =
((3x²−29x+94)/(x−5)(x+1)(x−6)) - 3(x−5)(x−6)/(x+1)(x−5)(x−6) =
(3x²−29x+94-3x²+18x+15x-90)/(x+1)(x−5)(x−6) =
(4x+4)/(x+1)(x−5)(x−6) =
4(x+1)/(x+1)(x−5)(x−6) =
4/(x-5)(x-6) =
4/(x²-11x+30)
Orkar inte fixa parenteserna men lösningen framgår nog ändå.